06-16-2016, 07:38 AM
Quote:I think there's a simple way to explain this.Do you assume that the whole surface is sensitive to light, AND that the sensitivity per square mm is identical?
Take a MFT camera and a FF camera. Let's assume that the whole sensor surface is sensitive to light. The sensitivity per square mm is identical.
Do not attach a lens. Same lighting conditions.
Open the shutter for -say- 1/100sec on both cameras.
Now "count" the photons that have been "gathered" by both sensors.
Which one gathered more photons and by which factor ?
Note: number of photons = speed.
Then the FF sensor has captured about 4 times more photons.
Was this your point?