01-09-2019, 10:38 AM
(This post was last modified: 01-10-2019, 09:13 AM by Klaus.)
https://m.youtube.com/watch?v=algDFH8u9D...sn1bS0DxSw
Funnily this will be the highest resolution MFT camera ever then (32mp)
Chief Editor - opticallimits.com
Doing all things Canon, MFT, Sony and Fuji
For those who don't watch the details - no details - full details at NAB q2 of this year. I guess the sensor would have to be around 36MP to support 8k but maybe they are interleaving images or something to keep the density lower ?
32? 36??
8k is 7680 horizontal and 4320 vertical.
7680 / 4 = 1920.
1920 * 3 = 5760.
7680 * 5760 = 44.2Mp.
(01-10-2019, 02:26 PM)Brightcolours Wrote: 32? 36??
8k is 7680 horizontal and 4320 vertical.
7680 / 4 = 1920.
1920 * 3 = 5760.
7680 * 5760 = 44.2Mp. ?
8K width X "6K" width? Why?
8K width X 8K height is still 7680 (4x 1920) x 4320 (4x 1080). That's 33.2 Mpix, or if you define it old school. 31.6 Mpix (generally rounded to 32 Mpix).
Kind regards, Wim
Gear: Canon EOS R with 3 primes and 2 zooms, 4 EF-R adapters, Canon EOS 5 (analog), 9 Canon EF primes, a lone Canon EF zoom, 2 extenders, 2 converters, tubes; Olympus OM-D 1 Mk II & Pen F with 12 primes, 6 zooms, and 3 Metabones EF-MFT adapters ....
01-10-2019, 05:30 PM
(This post was last modified: 01-10-2019, 06:09 PM by Brightcolours.)
(01-10-2019, 04:33 PM)wim Wrote: (01-10-2019, 02:26 PM)Brightcolours Wrote: 32? 36??
8k is 7680 horizontal and 4320 vertical.
7680 / 4 = 1920.
1920 * 3 = 5760.
7680 * 5760 = 44.2Mp. ?
8K width X "6K" width? Why?
8K width X 8K height is still 7680 (4x 1920) x 4320 (4x 1080). That's 33.2 Mpix, or if you define it old school. 31.6 Mpix (generally rounded to 32 Mpix).
Kind regards, Wim Uhmm, no. You certainly do not get it.
8K width = 7680 pixels.
So, what is a 4/3rds sensor? 4x3 aspect ratio.
7680 x 4320 is 16 x 9, not 4x3. MFT is called MFT (MicroFourThirds, not MSN (MicroSixteenNineths))...
Now calculate how many MP the MFT sensor needs to have to do 8K video.
Indeed, exactly as I showed you: 44.2mp.
(01-10-2019, 05:30 PM)Brightcolours Wrote: (01-10-2019, 04:33 PM)wim Wrote: (01-10-2019, 02:26 PM)Brightcolours Wrote: 32? 36??
8k is 7680 horizontal and 4320 vertical.
7680 / 4 = 1920.
1920 * 3 = 5760.
7680 * 5760 = 44.2Mp. ?
8K width X "6K" width? Why?
8K width X 8K height is still 7680 (4x 1920) x 4320 (4x 1080). That's 33.2 Mpix, or if you define it old school. 31.6 Mpix (generally rounded to 32 Mpix).
Kind regards, Wim Uhmm, no. You certainly do not get it.
8K width = 7680 pixels.
So, what is a 4/3rds sensor? 4x3 aspect ratio.
7680 x 4320 is 16 x 9, not 4x3. MFT is called MFT (MicroFourThirds, not MSN (MicroSixteenNineths))...
Now calculate how many MP the MFT sensor needs to have to do 8K video.
Indeed, exactly as I showed you: 44.2mp. I actually did get that, but the question is whether a video-cam at 8K really needs 44 (or 42.3 old style) Mpix, or more specifically a 4:3 layout. It can still be a 4/3 sensor in size (diameter), and have an 8K layout. I should probably have been clearer on that.
So far, I've only seen it announced as a 32 Mpix camera, when a number is given, so I guess we'll have to wait and see.
However, density-wise it would indeed be a 42.3 or 44 Mpix sensor, so a bit over twice as dense as current implementations from Panasonic and Olympus.
Kind regards, Wim
Gear: Canon EOS R with 3 primes and 2 zooms, 4 EF-R adapters, Canon EOS 5 (analog), 9 Canon EF primes, a lone Canon EF zoom, 2 extenders, 2 converters, tubes; Olympus OM-D 1 Mk II & Pen F with 12 primes, 6 zooms, and 3 Metabones EF-MFT adapters ....
(01-10-2019, 09:30 PM)wim Wrote: (01-10-2019, 05:30 PM)Brightcolours Wrote: (01-10-2019, 04:33 PM)wim Wrote: (01-10-2019, 02:26 PM)Brightcolours Wrote: 32? 36??
8k is 7680 horizontal and 4320 vertical.
7680 / 4 = 1920.
1920 * 3 = 5760.
7680 * 5760 = 44.2Mp. ?
8K width X "6K" width? Why?
8K width X 8K height is still 7680 (4x 1920) x 4320 (4x 1080). That's 33.2 Mpix, or if you define it old school. 31.6 Mpix (generally rounded to 32 Mpix).
Kind regards, Wim Uhmm, no. You certainly do not get it.
8K width = 7680 pixels.
So, what is a 4/3rds sensor? 4x3 aspect ratio.
7680 x 4320 is 16 x 9, not 4x3. MFT is called MFT (MicroFourThirds, not MSN (MicroSixteenNineths))...
Now calculate how many MP the MFT sensor needs to have to do 8K video.
Indeed, exactly as I showed you: 44.2mp. I actually did get that, but the question is whether a video-cam at 8K really needs 44 (or 42.3 old style) Mpix, or more specifically a 4:3 layout. It can still be a 4/3 sensor in size (diameter), and have an 8K layout. I should probably have been clearer on that.
So far, I've only seen it announced as a 32 Mpix camera, when a number is given, so I guess we'll have to wait and see.
However, density-wise it would indeed be a 42.3 or 44 Mpix sensor, so a bit over twice as dense as current implementations from Panasonic and Olympus.
Kind regards, Wim
The camera clearly is not a video camera, but a photo camera with 8K video (see form factor).
What makes MFT is the 4x3 aspect ratio.
What is the diamater of a rectangle?
01-12-2019, 12:21 AM
(This post was last modified: 01-12-2019, 12:22 AM by Klaus.)
Just for reference - the 4K Blackmagic MFT camera has a sensor size of 18.96mm x 10mm.
I suspect that Sharp will follow that approach (given the similarities in design I wouldn't be surprised if the Blackmagic camera is actually made by Sharp).
https://www.blackmagicdesign.com/au/products/blackmagicpocketcinemacamera/techspecs/W-CIN-12
Chief Editor - opticallimits.com
Doing all things Canon, MFT, Sony and Fuji
(01-11-2019, 12:06 PM)Brightcolours Wrote: (01-10-2019, 09:30 PM)wim Wrote: (01-10-2019, 05:30 PM)Brightcolours Wrote: (01-10-2019, 04:33 PM)wim Wrote: (01-10-2019, 02:26 PM)Brightcolours Wrote: 32? 36??
8k is 7680 horizontal and 4320 vertical.
7680 / 4 = 1920.
1920 * 3 = 5760.
7680 * 5760 = 44.2Mp. ?
8K width X "6K" width? Why?
8K width X 8K height is still 7680 (4x 1920) x 4320 (4x 1080). That's 33.2 Mpix, or if you define it old school. 31.6 Mpix (generally rounded to 32 Mpix).
Kind regards, Wim Uhmm, no. You certainly do not get it.
8K width = 7680 pixels.
So, what is a 4/3rds sensor? 4x3 aspect ratio.
7680 x 4320 is 16 x 9, not 4x3. MFT is called MFT (MicroFourThirds, not MSN (MicroSixteenNineths))...
Now calculate how many MP the MFT sensor needs to have to do 8K video.
Indeed, exactly as I showed you: 44.2mp. I actually did get that, but the question is whether a video-cam at 8K really needs 44 (or 42.3 old style) Mpix, or more specifically a 4:3 layout. It can still be a 4/3 sensor in size (diameter), and have an 8K layout. I should probably have been clearer on that.
So far, I've only seen it announced as a 32 Mpix camera, when a number is given, so I guess we'll have to wait and see.
However, density-wise it would indeed be a 42.3 or 44 Mpix sensor, so a bit over twice as dense as current implementations from Panasonic and Olympus.
Kind regards, Wim
The camera clearly is not a video camera, but a photo camera with 8K video (see form factor).
What makes MFT is the 4x3 aspect ratio.
What is the diamater of a rectangle? It is about the diameter of the (usable) image circle, not really about the diameter of the rectangle, AFAIAC.
(01-12-2019, 12:21 AM)Klaus Wrote: Just for reference - the 4K Blackmagic MFT camera has a sensor size of 18.96mm x 10mm.
I suspect that Sharp will follow that approach (given the similarities in design I wouldn't be surprised if the Blackmagic camera is actually made by Sharp).
https://www.blackmagicdesign.com/au/products/blackmagicpocketcinemacamera/techspecs/W-CIN-12
This indeed.
Kind regards, Wim
Gear: Canon EOS R with 3 primes and 2 zooms, 4 EF-R adapters, Canon EOS 5 (analog), 9 Canon EF primes, a lone Canon EF zoom, 2 extenders, 2 converters, tubes; Olympus OM-D 1 Mk II & Pen F with 12 primes, 6 zooms, and 3 Metabones EF-MFT adapters ....
Similarities in design? Really?
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